from collections import Counter
def solution(v):
ans = []
v1 = sum(v,[])
v_x = v1[0::2]
v_y = v1[1::2]
counts_x = Counter(v_x)
for element, value in counts_x.items():
if value%2 != 0:
ans.append(element)
counts_y = Counter(v_y)
for element, value in counts_y.items():
if value%2 != 0:
ans.append(element)
return ans
를 하면 소문자 알파벳을 순서대로 나열한 리스트가 생성된다. 라이브러리를 알고 있으면 편리하니까 외우도록 하기!!
from string import ascii_lowercase
def solution(s, skip, index):
al_list = list(ascii_lowercase)
answer = []
for i in range(len(skip)):
del al_list[al_list.index(skip[i])]
for i in range(len(s)):
ans = al_list[(al_list.index(s[i])+index) %len(al_list)]
answer.append(ans)
return ''.join(answer)
def solution(survey, choices):
answer = ''
score_dict = {'R':0, 'T':0, 'C':0, 'F':0, 'J':0, 'M':0, 'A':0, 'N':0}
scores = [3,2,1,0,1,2,3]
for i in range(len(survey)):
a = survey[i][0]
b = survey[i][1]
if choices[i] - 4 > 0:
score_dict[b] += scores[choices[i]-1]
elif choices[i] -4 < 0:
score_dict[a] += scores[choices[i]-1]
else:
continue
answer += "R" if score_dict["R"] >= score_dict["T"] else "T"
answer += "C" if score_dict["C"] >= score_dict["F"] else "F"
answer += "J" if score_dict["J"] >= score_dict["M"] else "M"
answer += "A" if score_dict["A"] >= score_dict["N"] else "N"
return answer
❤️다른 사람 코드 참고
def solution(survey, choices):
my_dict = {"RT":0,"CF":0,"JM":0,"AN":0}
for A,B in zip(survey,choices):
if A not in my_dict.keys():
A = A[::-1]
my_dict[A] -= B-4
else:
my_dict[A] += B-4
result = ""
for name in my_dict.keys():
if my_dict[name] > 0:
result += name[1]
elif my_dict[name] < 0:
result += name[0]
else:
result += sorted(name)[0]
return result